Complex.Cos(Complex) 方法
定义
重要
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返回指定复数的余弦值。
public:
static System::Numerics::Complex Cos(System::Numerics::Complex value);public static System.Numerics.Complex Cos(System.Numerics.Complex value);static member Cos : System.Numerics.Complex -> System.Numerics.ComplexPublic Shared Function Cos (value As Complex) As Complex参数
- value
- Complex
复数。
返回
value的余弦值。
示例
以下示例演示了 Acos 方法。 它显示，将 Acos 方法返回的值传递给 Cos 方法将返回原始 Complex 值。
using System;
using System.Numerics;
public class Example
{
public static void Main()
{
Complex[] values = { new Complex(.5, 2),
new Complex(.5, -2),
new Complex(-.5, 2),
new Complex(-.3, -.8) };
foreach (Complex value in values)
Console.WriteLine("Cos(ACos({0})) = {1}", value,
Complex.Cos(Complex.Acos(value)));
}
}
// The example displays the following output:
// Cos(ACos((0.5, 2))) = (0.5, 2)
// Cos(ACos((0.5, -2))) = (0.5, -2)
// Cos(ACos((-0.5, 2))) = (-0.5, 2)
// Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
open System.Numerics
let values =
[ Complex(0.5, 2.); Complex(0.5, -2.); Complex(-0.5, 2.); Complex(-0.3, -0.8) ]
for value in values do
printfn $"Cos(ACos({value})) = {Complex.Acos value |> Complex.Cos}"
// The example displays the following output:
// Cos(ACos((0.5, 2))) = (0.5, 2)
// Cos(ACos((0.5, -2))) = (0.5, -2)
// Cos(ACos((-0.5, 2))) = (-0.5, 2)
// Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
Imports System.Numerics
Module Example
Public Sub Main()
Dim values() As Complex = { New Complex(.5, 2),
New Complex(.5, -2),
New Complex(-.5, 2),
New Complex(-.3, -.8) }
For Each value As Complex In values
Console.WriteLine("Cos(ACos({0})) = {1}", value,
Complex.Cos(Complex.Acos(value)))
Next
End Sub
End Module
' The example displays the following output:
' Cos(ACos((0.5, 2))) = (0.5, 2)
' Cos(ACos((0.5, -2))) = (0.5, -2)
' Cos(ACos((-0.5, 2))) = (-0.5, 2)
' Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
注解
Cos 方法将复数 a + bi 的余弦值计算为 x + yi，其中：
-
x是 $\cos a \times \cosh b$ -
y为 $-（\sin a \times \sinh b）$
