Complex.Add 方法

定义

重载

示例

下面的示例演示如何加法复数。

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values= { new Complex(12.3, -1.4),
                          new Complex(-6.2, 3.1),
                          new Complex(8.9, 1.5) };
      foreach (var c1 in values)
         foreach (var c2 in values)
            Console.WriteLine("{0} + {1} = {2}", c1, c2,
                              Complex.Add(c1, c2));
   }
}
// The example displays the following output:
//       (12.3, -1.4) + (12.3, -1.4) = (24.6, -2.8)
//       (12.3, -1.4) + (-6.2, 3.1) = (6.1, 1.7)
//       (12.3, -1.4) + (8.9, 1.5) = (21.2, 0.1)
//       (-6.2, 3.1) + (12.3, -1.4) = (6.1, 1.7)
//       (-6.2, 3.1) + (-6.2, 3.1) = (-12.4, 6.2)
//       (-6.2, 3.1) + (8.9, 1.5) = (2.7, 4.6)
//       (8.9, 1.5) + (12.3, -1.4) = (21.2, 0.1)
//       (8.9, 1.5) + (-6.2, 3.1) = (2.7, 4.6)
//       (8.9, 1.5) + (8.9, 1.5) = (17.8, 3)

open System.Numerics

let values = [ Complex(12.3, -1.4); Complex(-6.2, 3.1); Complex(8.9, 1.5) ]

for c1 in values do
    for c2 in values do
        printfn $"{c1} + {c2} = {Complex.Add(c1, c2)}"
// The example displays the following output:
//       (12.3, -1.4) + (12.3, -1.4) = (24.6, -2.8)
//       (12.3, -1.4) + (-6.2, 3.1) = (6.1, 1.7)
//       (12.3, -1.4) + (8.9, 1.5) = (21.2, 0.1)
//       (-6.2, 3.1) + (12.3, -1.4) = (6.1, 1.7)
//       (-6.2, 3.1) + (-6.2, 3.1) = (-12.4, 6.2)
//       (-6.2, 3.1) + (8.9, 1.5) = (2.7, 4.6)
//       (8.9, 1.5) + (12.3, -1.4) = (21.2, 0.1)
//       (8.9, 1.5) + (-6.2, 3.1) = (2.7, 4.6)
//       (8.9, 1.5) + (8.9, 1.5) = (17.8, 3)

Imports System.Numerics

Module modMain
   Public Sub Main()
      Dim values() As Complex = { New Complex(12.3, -1.4), 
                                  New Complex(-6.2, 3.1), 
                                  New Complex(8.9, 1.5) }   
      For Each c1 In values
         For Each c2 In values
            Console.WriteLine("{0} + {1} = {2}", c1, c2, 
                              Complex.Add(c1, c2))
         Next
      Next      
   End Sub
End Module
' The example displays the following output:
'       (12.3, -1.4) + (12.3, -1.4) = (24.6, -2.8)
'       (12.3, -1.4) + (-6.2, 3.1) = (6.1, 1.7)
'       (12.3, -1.4) + (8.9, 1.5) = (21.2, 0.1)
'       (-6.2, 3.1) + (12.3, -1.4) = (6.1, 1.7)
'       (-6.2, 3.1) + (-6.2, 3.1) = (-12.4, 6.2)
'       (-6.2, 3.1) + (8.9, 1.5) = (2.7, 4.6)
'       (8.9, 1.5) + (12.3, -1.4) = (21.2, 0.1)
'       (8.9, 1.5) + (-6.2, 3.1) = (2.7, 4.6)
'       (8.9, 1.5) + (8.9, 1.5) = (17.8, 3)

注解

Add 方法允许执行涉及复数的加法运算。

如果方法调用导致实际组件或虚组件溢出，则组件的值 Double.PositiveInfinity 或 Double.NegativeInfinity。

不支持自定义运算符的语言可以使用 Add 方法执行复数加法。

接收一双双的 Add 方法比接收两个复数的方法更有效。

public:
 static System::Numerics::Complex Add(double left, System::Numerics::Complex right);

public static System.Numerics.Complex Add(double left, System.Numerics.Complex right);

static member Add : double * System.Numerics.Complex -> System.Numerics.Complex

Public Shared Function Add (left As Double, right As Complex) As Complex

public:
 static System::Numerics::Complex Add(System::Numerics::Complex left, double right);

public static System.Numerics.Complex Add(System.Numerics.Complex left, double right);

static member Add : System.Numerics.Complex * double -> System.Numerics.Complex

Public Shared Function Add (left As Complex, right As Double) As Complex

public:
 static System::Numerics::Complex Add(System::Numerics::Complex left, System::Numerics::Complex right);

public static System.Numerics.Complex Add(System.Numerics.Complex left, System.Numerics.Complex right);

static member Add : System.Numerics.Complex * System.Numerics.Complex -> System.Numerics.Complex

Public Shared Function Add (left As Complex, right As Complex) As Complex