Int16.MinValue 字段 
定义
重要
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表示 Int16 的最小可能值。 此字段为常数。
public: short MinValue = -32768;public const short MinValue = -32768;val mutable MinValue : int16Public Const MinValue As Short  = -32768字段值
Value = -32768示例
下面的示例使用 MinValue 属性在转换为Int16值时阻止 OverflowException 。
array<Int64>^ numbersToConvert = {162345, 32183, -54000};
Int16 newNumber;
for each (Int64 number in numbersToConvert)
{
   if (number >= Int16::MinValue && number <= Int16::MaxValue)
   {
      newNumber = Convert::ToInt16(number);
      Console::WriteLine("Successfully converted {0} to an Int16.", 
                         newNumber);
   }
   else
   {
      Console::WriteLine("Unable to convert {0} to an Int16.", number);
   }
}
// The example displays the following output:
//       Unable to convert 162345 to an Int16.
//       Successfully converted 32183 to an Int16.
//       Unable to convert -54000 to an Int16.
long[] numbersToConvert = {162345, 32183, -54000};
short newNumber;
foreach (long number in numbersToConvert)
{
   if (number >= Int16.MinValue && number <= Int16.MaxValue)
   {
      newNumber = Convert.ToInt16(number);
      Console.WriteLine($"Successfully converted {newNumber} to an Int16.");
   }
   else
   {
      Console.WriteLine($"Unable to convert {number} to an Int16.");
   }
}
// The example displays the following output to the console:
//       Unable to convert 162345 to an Int16.
//       Successfully converted 32183 to an Int16.
//       Unable to convert -54000 to an Int16.
open System
let numbersToConvert = [ 162345L; 32183L; -54000L ]
for number in numbersToConvert do
    if number >= int64 Int16.MinValue && number <= int64 Int16.MaxValue then
        let newNumber = Convert.ToInt16 number
        printfn $"Successfully converted {newNumber} to an Int16."
    else
        printfn $"Unable to convert {number} to an Int16."
// The example displays the following output to the console:
//       Unable to convert 162345 to an Int16.
//       Successfully converted 32183 to an Int16.
//       Unable to convert -54000 to an Int16.
Dim numbersToConvert() As Long = {162345, 32183, -54000}
Dim newNumber As Int16
For Each number As Long In NumbersToConvert
   If number >= Int16.MinValue And number <= Int16.MaxValue Then
      newNumber = Convert.ToInt16(number)
      Console.WriteLine("Successfully converted {0} to an Int16.", _
                        newNumber)
   Else
      Console.WriteLine("Unable to convert {0} to an Int16.", number)
   End If                     
Next
' The example displays the following output to the console:
'       Unable to convert 162345 to an Int16.
'       Successfully converted 32183 to an Int16.
'       Unable to convert -54000 to an Int16.
注解
此常量的值为 -32768;即十六进制0x8000。
属性 MinValue 通常用于防止 OverflowException 从具有较大较小范围的数字类型转换为 (如 Int32 或 Int64) 到 Int16。 该示例演示了此用法。