DataGridItem.DataItem Property
Definition
Important
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Gets or sets the data item represented by the DataGridItem object in the DataGrid control.
public:
virtual property System::Object ^ DataItem { System::Object ^ get(); void set(System::Object ^ value); };public virtual object DataItem { get; set; }member this.DataItem : obj with get, setPublic Overridable Property DataItem As ObjectProperty Value
A Object that represents a data item in the DataGrid control.
Examples
The following code example demonstrates how to use the DataItem property to display the contents of the data items in the DataGrid control.
Note
The following code example uses the single-file code model and might not work correctly if copied directly into a code-behind file. This code example must be copied into an empty text file that has an .aspx extension.
<%@ Page Language="C#" AutoEventWireup="True" %>
<%@ Import Namespace="System.Data" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<script language="C#" runat="server">
DataTable Cart;
DataView CartView;
ICollection CreateDataSource()
{
DataTable dt = new DataTable();
DataRow dr;
dt.Columns.Add(new DataColumn("IntegerValue", typeof(Int32)));
dt.Columns.Add(new DataColumn("StringValue", typeof(string)));
dt.Columns.Add(new DataColumn("CurrencyValue", typeof(double)));
for (int i = 0; i < 10; i++)
{
dr = dt.NewRow();
dr[0] = i;
dr[1] = "Item " + i.ToString();
dr[2] = 1.23 * (i+1);
dt.Rows.Add(dr);
}
DataView dv = new DataView(dt);
return dv;
}
void Page_Load(Object sender, EventArgs e)
{
if (!IsPostBack)
{
// Need to load this data only once.
ItemsGrid.DataSource = CreateDataSource();
ItemsGrid.DataBind();
}
}
void Item_Created(Object sender, DataGridItemEventArgs e)
{
if (e.Item.ItemType == ListItemType.Item ||
e.Item.ItemType == ListItemType.AlternatingItem ||
e.Item.ItemType == ListItemType.SelectedItem ||
e.Item.ItemType == ListItemType.EditItem)
{
Label1.Text += "<br />" + e.Item.ItemType.ToString() +
" - " + ((DataRowView)e.Item.DataItem).Row.ItemArray[1].ToString();
}
else
{
Label1.Text += "<br />" + e.Item.ItemType.ToString();
}
}
</script>
<head runat="server">
<title>DataGridItem DataItem Example</title>
</head>
<body>
<form id="form1" runat="server">
<h3>DataGridItem DataItem Example</h3>
<asp:DataGrid id="ItemsGrid" runat="server"
BorderColor="black"
BorderWidth="1"
CellPadding="3"
ShowFooter="true"
OnItemCreated="Item_Created"
AutoGenerateColumns="true">
<HeaderStyle BackColor="#00aaaa">
</HeaderStyle>
<FooterStyle BackColor="#00aaaa">
</FooterStyle>
</asp:DataGrid>
<br />
<asp:Label id="Label1"
Text="Items in the DataGrid Control: <br />"
runat="server"/>
</form>
</body>
</html>
<%@ Page Language="VB" AutoEventWireup="True" %>
<%@ Import Namespace="System.Data" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<script language="VB" runat="server">
Dim Cart As DataTable
Dim CartView As DataView
Function CreateDataSource() As ICollection
Dim dt As New DataTable()
Dim dr As DataRow
dt.Columns.Add(New DataColumn("IntegerValue", GetType(Int32)))
dt.Columns.Add(New DataColumn("StringValue", GetType(String)))
dt.Columns.Add(New DataColumn("CurrencyValue", GetType(Double)))
Dim i As Integer
For i = 0 To 9
dr = dt.NewRow()
dr(0) = i
dr(1) = "Item " & i.ToString()
dr(2) = 1.23 *(i + 1)
dt.Rows.Add(dr)
Next i
Dim dv As New DataView(dt)
Return dv
End Function 'CreateDataSource
Sub Page_Load(sender As Object, e As EventArgs)
If Not IsPostBack Then
' Need to load this data only once.
ItemsGrid.DataSource = CreateDataSource()
ItemsGrid.DataBind()
End If
End Sub 'Page_Load
Sub Item_Created(sender As Object, e As DataGridItemEventArgs)
If e.Item.ItemType = ListItemType.Item Or e.Item.ItemType = ListItemType.AlternatingItem Or e.Item.ItemType = ListItemType.SelectedItem Or e.Item.ItemType = ListItemType.EditItem Then
Label1.Text &= "<br />" & e.Item.ItemType.ToString() & " - " & CType(e.Item.DataItem, DataRowView).Row.ItemArray(1).ToString()
Else
Label1.Text &= "<br />" & e.Item.ItemType.ToString()
End If
End Sub 'Item_Created
</script>
<head runat="server">
<title>DataGridItem DataItem Example</title>
</head>
<body>
<form id="form1" runat="server">
<h3>DataGridItem DataItem Example</h3>
<asp:DataGrid id="ItemsGrid" runat="server"
BorderColor="black"
BorderWidth="1"
CellPadding="3"
ShowFooter="true"
OnItemCreated="Item_Created"
AutoGenerateColumns="true">
<HeaderStyle BackColor="#00aaaa">
</HeaderStyle>
<FooterStyle BackColor="#00aaaa">
</FooterStyle>
</asp:DataGrid>
<br />
<asp:Label id="Label1"
Text="Items in the DataGrid Control: <br />"
runat="server"/>
</form>
</body>
</html>
Remarks
Use the DataItem property to specify or determine the properties of a data item represented by the DataGridItem object in the DataGrid control.
Note
This property applies only to data items in the DataGrid control. The ItemType property must be set to ListItemType.Item, ListItemType.AlternatingItem, ListItemType.SelectedItem, or ListItemType.EditItem.
