Uri.SchemeDelimiter Field

public: static initonly System::String ^ SchemeDelimiter;

public static readonly string SchemeDelimiter;

 staticval mutable SchemeDelimiter : string

Public Shared ReadOnly SchemeDelimiter As String 

Field Value

Examples

The following example creates a string from UriSchemeHttp, SchemeDelimiter, and an address. A Uri instance is then created from the string.

            string address = "www.contoso.com";
            string uriString = String.Format("{0}{1}{2}/", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address);
 #if OLDMETHOD
            Uri result;
            if (Uri.TryParse(uriString, false, false, out result))
                Console.WriteLine("{0} is a valid Uri", result.ToString());
            else
                Console.WriteLine("Uri not created");
#endif
            Uri result = new Uri(uriString);
            if (result.IsWellFormedOriginalString())
                Console.WriteLine("{0} is a well formed Uri", uriString);
            else
                Console.WriteLine("{0} is not a well formed Uri", uriString);

    let address = "www.contoso.com"
    let uriString = $"{Uri.UriSchemeHttp}{Uri.SchemeDelimiter}{address}/"
#if OLDMETHOD
    match Uri.TryParse(uriString, false, false) with
    | true, result ->
        printfn $"{result} is a valid Uri"
    | _ ->
        printfn "Uri not created"
#endif
    let result = Uri uriString
    if result.IsWellFormedOriginalString() then
        printfn $"{uriString} is a well formed Uri"
    else
        printfn $"{uriString} is not a well formed Uri"

Dim address As String = "www.contoso.com"
Dim uriString As String = String.Format("{0}{1}{2}", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address)

Dim result As Uri = New Uri(uriString)

If result.IsWellFormedOriginalString() = True Then
    Console.WriteLine("{0} is a well formed Uri", uriString)
else
    Console.WriteLine("{0} is not a well formed Uri", uriString)
End If