Double.MinValue Field  
Definition
Important
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Represents the smallest possible value of a Double. This field is constant.
public: double MinValue = -1.7976931348623157E+308;public const double MinValue = -1.7976931348623157E+308;val mutable MinValue : doublePublic Const MinValue As Double  = -1.7976931348623157E+308Field Value
Value = -1.7976931348623157E+308Examples
The following code example illustrates the use of Double.MinValue:
public class Temperature {
    public static double MinValue {
        get {
            return Double.MinValue;
        }
    }
    public static double MaxValue {
        get {
            return Double.MaxValue;
        }
    }
    // The value holder
    protected double m_value;
    public double Value {
        get {
            return m_value;
        }
        set {
            m_value = value;
        }
    }
    public double Celsius {
        get {
            return (m_value-32.0)/1.8;
        }
        set {
            m_value = 1.8*value+32.0;
        }
    }
}
type Temperature() =
    static member MinValue =
        Double.MinValue
    static member MaxValue =
        Double.MaxValue
    member val Value = 0. with get, set
    member this.Celsius
        with get () =
            (this.Value - 32.) / 1.8
        and set (value) =
            this.Value <- 1.8 * value + 32.
Public Class Temperature
    Public Shared ReadOnly Property MinValue() As Double
        Get
            Return Double.MinValue
        End Get
    End Property
    Public Shared ReadOnly Property MaxValue() As Double
        Get
            Return Double.MaxValue
        End Get
    End Property
    ' The value holder
    Protected m_value As Double
    Public Property Value() As Double
        Get
            Return m_value
        End Get
        Set(ByVal Value As Double)
            m_value = Value
        End Set
    End Property
    Public Property Celsius() As Double
        Get
            Return (m_value - 32) / 1.8
        End Get
        Set(ByVal Value As Double)
            m_value = Value * 1.8 + 32
        End Set
    End Property
End Class
Remarks
The value of this constant is negative 1.7976931348623157E+308.
The result of an operation that is less than Double.MinValue is Double.NegativeInfinity. In the following example, Double.NegativeInfinity results from subtraction and multiplication operations when the result is less than Double.MinValue.
using System;
public class Example
{
   public static void Main()
   {
      double result1 = -7.997e307 + -9.985e307;
      Console.WriteLine("{0} (Negative Infinity: {1})",
                        result1, Double.IsNegativeInfinity(result1));
      double result2 = -1.5935e250 * 7.948e110;
      Console.WriteLine("{0} (Negative Infinity: {1})",
                        result2, Double.IsNegativeInfinity(result2));
   }
}
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)
open System
let result1 = -7.997e307 + -9.985e307
printfn $"{result1} (Negative Infinity: {Double.IsNegativeInfinity result1})"
let result2 = -1.5935e250 * 7.948e110
printfn $"{result2} (Negative Infinity: {Double.IsNegativeInfinity result2})"
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)
Module Example
   Public Sub Main()
      Dim result1 As Double = -7.997e307 + -9.985e307
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result1, Double.IsNegativeInfinity(result1))
      
      Dim result2 As Double = -1.5935e250 * 7.948e110
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result2, Double.IsNegativeInfinity(result2))
   End Sub
End Module
' The example displays the following output:
'    -Infinity (Negative Infinity: True)
'    -Infinity (Negative Infinity: True)