has_virtual_destructor Class

2013-02-24

，如果类型具有虚析构函数，测试。

template<class Ty>
    struct has_virtual_destructor;

参数

Ty
查询的类型。

备注

该类型特性的实例适合，如果类型 Ty 是一个具有虚析构函数的类，否则它包含错误。

示例

// std_tr1__type_traits__has_virtual_destructor.cpp 
// compile with: /EHsc 
#include <type_traits> 
#include <iostream> 
 
struct trivial 
    { 
    int val; 
    }; 
 
struct throws 
    { 
    throws() throw(int) 
        { 
        } 
 
    throws(const throws&) throw(int) 
        { 
        } 
 
    throws& operator=(const throws&) throw(int) 
        { 
        } 
 
    virtual ~throws() 
        { 
        } 
 
    int val; 
    }; 
 
int main() 
    { 
    std::cout << "has_virtual_destructor<trivial> == " << std::boolalpha 
        << std::has_virtual_destructor<trivial>::value << std::endl; 
    std::cout << "has_virtual_destructor<throws> == " << std::boolalpha 
        << std::has_virtual_destructor<throws>::value << std::endl; 
 
    return (0); 
    }