Font.Equals(Object) 方法 
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
指示指定的对象是否为 Font,并且具有与此 Font相同的 FontFamily、GdiVerticalFont、GdiCharSet、Style、Size和 Unit 属性值。
public:
 override bool Equals(System::Object ^ obj);
	public override bool Equals (object? obj);
	public override bool Equals (object obj);
	override this.Equals : obj -> bool
	Public Overrides Function Equals (obj As Object) As Boolean
	参数
- obj
 - Object
 
要测试的对象。
返回
如果 obj 参数是 Font 且具有与此 Font相同的 FontFamily、GdiVerticalFont、GdiCharSet、Style、Size和 Unit 属性值,则 true;否则,false。
示例
下面的代码示例设计用于 Windows 窗体,它需要 PaintEventArgse,这是 Paint 事件处理程序的参数。 该代码创建两个 Font 对象,然后测试它们是否等效。
public:
   void Equals_Example( PaintEventArgs^ /*e*/ )
   {
      // Create a Font object.
      System::Drawing::Font^ firstFont = gcnew System::Drawing::Font( "Arial",16 );
      // Create a second Font object.
      System::Drawing::Font^ secondFont = gcnew System::Drawing::Font( gcnew FontFamily( "Arial" ),16 );
      // Test to see if firstFont is identical to secondFont.
      bool fontTest = firstFont->Equals( secondFont );
      // Display a message box with the result of the test.
      MessageBox::Show( fontTest.ToString() );
   }
public void Equals_Example(PaintEventArgs e)
{
    // Create a Font object.
    Font firstFont = new Font("Arial", 16);
             
    // Create a second Font object.
    Font secondFont = new Font(new FontFamily("Arial"), 16);
             
    // Test to see if firstFont is identical to secondFont.
    bool fontTest = firstFont.Equals(secondFont);
             
    // Display a message box with the result of the test.
    MessageBox.Show(fontTest.ToString());
}
Public Sub Equals_Example(ByVal e As PaintEventArgs)
    ' Create a Font object.
    Dim firstFont As New Font("Arial", 16)
    ' Create a second Font object.
    Dim secondFont As New Font(New FontFamily("Arial"), 16)
    ' Test to see if firstFont is identical to secondFont.
    Dim fontTest As Boolean = firstFont.Equals(secondFont)
    ' Display a message box with the result of the test.
    MessageBox.Show(fontTest.ToString())
End Sub