HttpRequestExecutor.PreProcess Method    
Definition
Important
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Prepare a request for sending.
[Android.Runtime.Register("preProcess", "(Lorg/apache/http/HttpRequest;Lorg/apache/http/protocol/HttpProcessor;Lorg/apache/http/protocol/HttpContext;)V", "GetPreProcess_Lorg_apache_http_HttpRequest_Lorg_apache_http_protocol_HttpProcessor_Lorg_apache_http_protocol_HttpContext_Handler")]
public virtual void PreProcess(Org.Apache.Http.IHttpRequest? request, Org.Apache.Http.Protocol.IHttpProcessor? processor, Org.Apache.Http.Protocol.IHttpContext? context);
	[<Android.Runtime.Register("preProcess", "(Lorg/apache/http/HttpRequest;Lorg/apache/http/protocol/HttpProcessor;Lorg/apache/http/protocol/HttpContext;)V", "GetPreProcess_Lorg_apache_http_HttpRequest_Lorg_apache_http_protocol_HttpProcessor_Lorg_apache_http_protocol_HttpContext_Handler")>]
abstract member PreProcess : Org.Apache.Http.IHttpRequest * Org.Apache.Http.Protocol.IHttpProcessor * Org.Apache.Http.Protocol.IHttpContext -> unit
override this.PreProcess : Org.Apache.Http.IHttpRequest * Org.Apache.Http.Protocol.IHttpProcessor * Org.Apache.Http.Protocol.IHttpContext -> unit
	Parameters
- request
 - IHttpRequest
 
the request to prepare
- processor
 - IHttpProcessor
 
the processor to use
- context
 - IHttpContext
 
the context for sending the request
- Attributes
 
Exceptions
in case of a protocol or processing problem
in case of an I/O problem
Remarks
Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.