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Tests if one type is convertible to another.
Syntax
template <class From, class To>
struct is_convertible;
Parameters
From
The type to convert from.
Ty
The type to convert to.
Remarks
An instance of the type predicate holds true if the expression To to = from;, where from is an object of type From, is well-formed.
Example
// std__type_traits__is_convertible.cpp
// compile with: /EHsc
#include <type_traits>
#include <iostream>
struct trivial
{
int val;
};
int main()
{
std::cout << "is_convertible<trivial, int> == " << std::boolalpha
<< std::is_convertible<trivial, int>::value << std::endl;
std::cout << "is_convertible<trivial, trivial> == " << std::boolalpha
<< std::is_convertible<trivial, trivial>::value << std::endl;
std::cout << "is_convertible<char, int> == " << std::boolalpha
<< std::is_convertible<char, int>::value << std::endl;
return (0);
}
is_convertible<trivial, int> == false
is_convertible<trivial, trivial> == true
is_convertible<char, int> == true
Requirements
Header: <type_traits>
Namespace: std