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Returns the element that a reverse_iterator addresses.
reference operator*( ) const;
Return Value
The value of the elements addressed by the reverse_iterator.
Remarks
The operator returns *(current – 1).
Example
// reverse_iterator_op_ref.cpp
// compile with: /EHsc
#include <iterator>
#include <algorithm>
#include <vector>
#include <iostream>
int main( )
{
   using namespace std;
   int i;
   vector<int> vec;
   for (i = 1 ; i < 6 ; ++i )  
   {
      vec.push_back ( 2 * i );
   }
   
   vector <int>::iterator vIter;
   cout << "The vector vec is: ( ";
   for ( vIter = vec.begin ( ) ; vIter != vec.end ( ); vIter++ )
      cout << *vIter << " ";
   cout << ")." << endl;
   vector <int>::reverse_iterator rvIter;
   cout << "The vector vec reversed is: ( ";
   for ( rvIter = vec.rbegin( ) ; rvIter != vec.rend( ); rvIter+)
      cout << *rvIter << " ";
   cout << ")." << endl;
   vector <int>::iterator pos, bpos;
   pos = find ( vec.begin ( ), vec.end ( ), 6 );
   // Declare a difference type for a parameter
   // declare a reference return type
   reverse_iterator<vector<int>::iterator>::reference refpos = *pos;
   cout << "The iterator pos points to: " << refpos << "." << endl;
}
Output
The vector vec is: ( 2 4 6 8 10 ).
The vector vec reversed is: ( 10 8 6 4 2 ).
The iterator pos points to: 6.
Requirements
Header: <iterator>
Namespace: std