OpCodes.Rem_Un Field  
Definition
Important
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Divides two unsigned values and pushes the remainder onto the evaluation stack.
public: static initonly System::Reflection::Emit::OpCode Rem_Un;public static readonly System.Reflection.Emit.OpCode Rem_Un; staticval mutable Rem_Un : System.Reflection.Emit.OpCodePublic Shared ReadOnly Rem_Un As OpCode Field Value
Remarks
The following table lists the instruction's hexadecimal and Microsoft Intermediate Language (MSIL) assembly format, along with a brief reference summary:
| Format | Assembly Format | Description | 
|---|---|---|
| 5E | rem.un | Pushes the remainder of dividing unsigned value1by unsignedvalue2onto the stack. | 
The stack transitional behavior, in sequential order, is:
- value1is pushed onto the stack.
- value2is pushed onto the stack.
- value2and- value1are popped from the stack and the remainder of- value1- div- value2computed.
- The result is pushed onto the stack. 
result = value1 rem.un value2 satisfies the following conditions:
result = value1 - value2 x(value1 div.un value2), and:
0 = result < value2, where div.un is the unsigned division instruction.
The rem.un instruction computes result and pushes it on the stack. Rem.un treats its arguments as unsigned integers, while Rem treats them as signed integers.
Rem.un is unspecified for floating-point numbers.
Integral operations throw DivideByZeroException if value2 is zero.
The following Emit method overload can use the rem.un opcode: