OpCodes.Ceq Field
Definition
Important
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Compares two values. If they are equal, the integer value 1 (int32) is pushed onto the evaluation stack; otherwise 0 (int32) is pushed onto the evaluation stack.
public: static initonly System::Reflection::Emit::OpCode Ceq;
public static readonly System.Reflection.Emit.OpCode Ceq;
staticval mutable Ceq : System.Reflection.Emit.OpCode
Public Shared ReadOnly Ceq As OpCode
Field Value
Remarks
The following table lists the instruction's hexadecimal and Microsoft Intermediate Language (MSIL) assembly format, along with a brief reference summary:
| Format | Assembly Format | Description |
|---|---|---|
| FE 01 | ceq | Pushes 1 if value1 equals value2; else pushes 0. |
The stack transitional behavior, in sequential order, is:
value1is pushed onto the stack.value2is pushed onto the stack.value2andvalue1are popped from the stack;value1is compared tovalue2.If
value1is equal tovalue2, 1 is pushed onto the stack; otherwise 0 is pushed onto the stack.
The ceq instruction compares value1 and value2. If value1 is equal to value2, then 1 (of type int32) is pushed on the stack. Otherwise 0 (of type int32) is pushed on the stack.
For floating-point number, ceq will return 0 if the numbers are unordered (either or both are NaN). The infinite values are equal to themselves.
The following Emit method overload can use the ceq opcode: